What voltage is the capacitors providing to the micro just after being fully charged?
This is what I have currently:
Code:
$ 1 4.9999999999999996E-5 105.18789638808724 50 5.0 50
z 384 272 384 176 1 1.2 5.1
r 320 272 320 176 0 15.0
r 544 192 544 384 0 100.0
c 352 272 352 320 2 10.0 2.4298641778297494
c 352 320 352 384 2 10.0 2.4298641778297494
w 352 384 448 384 0
w 448 384 544 384 0
w 544 192 544 176 0
g 448 384 448 432 0
w 384 272 352 272 0
w 352 272 320 272 0
w 320 176 352 176 0
w 352 176 384 176 0
R 432 80 432 32 0 0 40.0 5.0 0.0 0.0 0.5
w 384 176 544 176 0
s 352 112 432 112 0 0 false
w 544 144 544 176 0
178 432 80 544 80 0 1 0.2 0.011428571428571427 0.05 1000000.0 0.0114 1050.0
w 432 128 432 304 0
w 432 304 448 304 0
w 448 304 448 384 0
w 544 96 544 144 0
R 352 112 304 112 0 0 40.0 12.0 0.0 0.0 0.5
o 3 64 0 35 2.5 0.05 0 -1
o 2 64 0 35 5.0 0.05 1 -1
The switch represents the computer being turned on and off. But this circuit currently prevents the capacitors trying to power everything in the computer via the relay. I've lowered the charging resistor from 100 ohms to 15 ohms to charge it a little faster. The other resistor represents the load on the system. I have another idea on how to get things working better... but I'm unsure on how to do it.
EDIT: Simulator is showing me that each capacitor is charging to 2.27v in 3 minutes. There could be another way of cutting the power to the arduino and servo after it finishes it's power down sequence using another relay if you're interested.